Cálculo en Variedades – Michael – Download as PDF File .pdf), Text File .txt) or read online. Cálculo en Variedades – Michael Spivak – Download as PDF File .pdf) or read online. Title, Cálculo en variedades. Author, Michael Spivak. Edition, illustrated, reprint. Publisher, Reverte, ISBN, ,

Author: Tojagul Vusida
Country: Honduras
Language: English (Spanish)
Genre: Health and Food
Published (Last): 8 February 2007
Pages: 399
PDF File Size: 1.26 Mb
ePub File Size: 2.5 Mb
ISBN: 430-3-57797-735-4
Downloads: 91523
Price: Free* [*Free Regsitration Required]
Uploader: Taull

Since is a linear map of a finite dimensional vector space into itself, it follows that is also onto.

Calculo En Variedades/ Calculus of Variations

No, you could, for example, vary at discrete points without changing the values of the integrals. Then part a gives the inequality of Theorem 2. If for some realthen substituting back into the equality shows that must be non-positive or must be 0. Prove that if is norm preserving, then is angle preserving. So since the integrand spivvak always non-negative it must be that its discriminant is negative.

Spivak – Calculus – of – Manifolds – Solutions (2)

In particular, has an inverse. Geometrically, if, and are the vertices of a triangle, then the inequality says that the length of a side is no larger than the sum of the lengths of the other two sides.

Further, giventhere is a withand so. On the other hand, ifthen the result follows The inequality follows from Theorem I claim that equality holds precisely when one vector is a non-positive multiple of the other. Then impliesi.


A linear transformation is called norm preserving if1. Further, maps each to a scalar multiple of varisdades so is a map of the type in part b.

This is a consequence of the analogous assertion of the next problem. If there is a basis of and numbers such thatprove variwdades is angle preserving if and only if all are equal. For the converse, suppose that is angle preserving.

Let be an orthogonal basis of. In enn, suppose that for eachthere is an with. The case where is treated similarly. Let be norm preserving. Define to be the linear transformation such that is angle preserving, the are also pairwise orthogonal. The linear transformation is angle preserving if is and for1. This completes the characterization.

Cálculo en variedades – Michael Spivak – Google Books

If and are continuous, then the assertion is true. Clearly, any of this form is angle preserving as the composition of two angle preserving linear transformations is angle preserving. The angle preserving are precisely those which can be expressed spigak the form where U is angle preserving of the kind in part bV is norm preserving, and the operation is functional composition.

Note, however, that the equality condition does not follow from a. Trabalho do Professor Wpivak Tung Yau. Parte 1 de Then the inequality holds true in an open neighborhood of since and are.


If for some realthen substituting shows that the inequality is equivalent to and clearly equality holds if a is non.

Michael David Spivak – Wikipedia, la enciclopedia libre

So, this condition suffices to make be angle preserving. Dalculo transformation is by Cramer’s Rule because the determinant of its matrix is 1. Equality holds precisely when one is a nonnegative multiple of the other. If and in are both non-zero, then the angle between anddenotedis defined to be which makes sense by Theorem 2.

So T is Further, is norm preserving since. Show that is norm preserving if and only if is inner product preserving. The first assertion is the triangle inequality. Similarly, if is norm preserving, then the polarization identity together with the linearity of T give:. To correct the situation, add the condition that the be pairwise orthogonal, because all the cross terms are variedadrs.